我有一个查询返回avg(price) E2 z6 L/ A5 M
select avg(price) from( select *,cume_dist() OVER (ORDER BY price desc) from web_price_scan where listing_Type='AARM and u_kbalikepartnumbers_id = and (EXTRACT(Day FROM (Now()-dateEnded)))*24 ( select avg(price)* 0.505050 from(select *,cume_dist() OVER (ORDER BY price desc) from web_price_scan where listing_Type='AARM and u_kbalikepartnumbers_id = and (EXTRACT(Day FROM (Now()-dateEnded)))*24 5如果没有可用值,如何返回0?8 g4 T ~5 n/ d, b, R/ H/ G
9 W& g$ I M. V) D; k ] 解决方案: + a# L! X4 y' Z. D' z8 z' X# W 使用合并 $ ^+ p/ S. m5 \4 n9 }COALESCE(value [,...])The COALESCE function returns the first of its arguments that is notnull.5 X: I Y2 C+ l+ B/ j F
Null is returned only if all arguments are null. It is often 3 l9 D* m8 k: ^ used to substitute a default value for null values when data is, a1 y2 e- ?0 ?
retrieved for display.* J; b5 z- O* N, u7 Y 编辑! V1 n% j& x' m, _; _ V
这是COALESCE查询示例: 2 p+ y& f S- tSELECT AVG( price )FROM( SELECT *,cume_dist() OVER ( ORDER BY price DESC ) FROM web_price_scan WHERE listing_Type = 'AARM AND u_kbalikepartnumbers_id = AND ( EXTRACT( DAY FROM ( NOW() - dateEnded ) ) * 24 ( SELECT AVG( COALESCE( price,0 ) )* 0.505050 FROM ( SELECT *,cume_dist() OVER ( ORDER BY price DESC ) FROM web_price_scan WHERE listing_Type='AARM AND u_kbalikepartnumbers_id = AND ( EXTRACT( DAY FROM ( NOW() - dateEnded ) ) * 24 5IMHOCOALESCE不应与之一起使用,AVG因为它会修改值。NULL这意味着未知,没有别的。这不像在里面用。SUM。在这个例子中,如果我们替换它,AVG为SUM,结果不会扭曲。总和加0不会伤害任何人,但当未知值计算为0时,你不会得到真正的平均值。* m, C! y ]0 M5 j d/ e8 f
在那种情况下,我将添加price IS NOT NULLinWHERE避免这些未知值。