CAS唤醒后继线程为什么是从后向前遍历5金钱.anslist{background:url(sourc

孖大

private void unparkSuccessor(Node node) {1 M9 N) y3 S% B! `% [
/*
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* If status is negative (i.e., possibly needing signal) try5 ~3 Y6 v( Y& S* Z6 n, y* Z
* to clear in anticipation of signalling. It is OK if this
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* fails or if status is changed by waiting thread.
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int ws = node.waitStatus;
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if (ws < 0)
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compareAndSetWaitStatus(node, ws, 0);
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/*+ o# h: n" [0 c0 u/ P% u
* Thread to unpark is held in successor, which is normally2 ^( A9 ~' I/ d4 N5 L5 @) r3 J
* just the next node. But if cancelled or apparently null,) Z5 d& T8 i. \$ [
* traverse backwards from tail to find the actual
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* non-cancelled successor.% R/ g: Z1 y, r7 [/ {
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Node s = node.next;$ D7 F( y C$ o
if (s == null || s.waitStatus > 0) {$ T! x6 S% Z4 \) A3 v
s = null;
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for (Node t = tail; t != null && t != node; t = t.prev)5 i- t, a1 f5 I) d- X. e5 x
if (t.waitStatus <= 0)# N) D. k) m# a0 v# S4 }) _7 s
s = t;6 X* b9 b" }1 x. |% p& Y7 b
}
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if (s != null)
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LockSupport.unpark(s.thread); }
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如果没有合法的数据，从后向前遍历，为什么这么做呢？从前向后不行吗？
我知道答案回答被采纳将会获得5 金钱已有0人回答

CAS唤醒后继线程 为什么是从后向前遍历5金钱.anslist{background:url(sourc